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A finite-difference grid has $1{,}000$ price points by $1{,}000$ time steps, stored as float64. How many megabytes does storing the whole grid take (1 MB $= 10^6$ bytes)?

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A finite-difference grid has 1,0001{,}0001,000 price points by 1,0001{,}0001,000 time steps, stored as float64. How many megabytes does storing the whole grid take (1 MB =106= 10^6=106 bytes)?

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A finite-difference grid has $1{,}000$ price points by $1{,}000$ time steps, stored as float64. How many megabytes does storing the whole grid take (1 MB $= 10^6$ bytes)?